Oculus Go VR Headset Launches in 2018 for $199

Oculus Go VR Headset Launches in 2018 for $199 - News

by William D'Angelo , posted on 12 October 2017 / 1,357 Views

Oculus has announced a new standalone virtual reality headset that will release in 2018. The Oculus Go  VR headset will release for $199.

It doesn't requires any cables or a smartphone to be used as a display.  The device will be "super lightweight" in order to make the best experience for users. 

"[The LCD display will] dramatically improve visual clarity and reduce screen door effect," said Oculus. Speakers will be built right into the headset, as well as a 3.5mm headphone jack. 

All Gear VR apps will be compatible with Oculus Go.

A life-long and avid gamer, William D'Angelo was first introduced to VGChartz in 2007. After years of supporting the site, he was brought on in 2010 as a junior analyst, working his way up to lead analyst in 2012. He has expanded his involvement in the gaming community by producing content on his own YouTube channel and Twitch channel dedicated to gaming Let's Plays and tutorials. You can contact the author at wdangelo@vgchartz.com or on Twitter @TrunksWD.


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6 Comments

Mar1217
Mar1217 (on 12 October 2017)

This might finally get me to try VR !!

  • +1
theDX
theDX (on 12 October 2017)

How did they make it so cheap? That's kind of amazing.

  • +1
Slap&Ride
Slap&Ride (on 13 October 2017)

""It doesn't requires any cables or a smartphone to be used as a display."" So it's an WiFi-LCD with a Strap-On?

  • 0
CrazyGamer2017
CrazyGamer2017 (on 12 October 2017)

Is it capable of real time movement tracking cause without it it's not VR to me. And I fear at that price it may not be. I hope it is but I fear it is not.

  • 0
Dgc1808
Dgc1808 (on 12 October 2017)

What manner of sorcery is this?

  • 0
gtotheunit91
gtotheunit91 (on 12 October 2017)

So does it have its own OS installed along with a store to buy/download any apps/games? Or would you have to hook it up to your PC and go to the Oculus Store still to get everything?

  • 0